Math, asked by devilq656, 1 month ago

In a right triangle RQP if PQ=5cm RQ=10cm find the value of :
(i) sin2P
(ii) tan R
(iii) sin P x cos P
(iv) sin2P - cos2 P

Answers

Answered by surendramehta355
0

Step-by-step explanation:

In △PQR, right angled at Q. If PQ=5 and RQ=10cm find sin

2

P.

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Answer

PR

2

=PQ

2

+QR

2

PR

2

=25+100

PR

2

=125

PR=

125

=5

5

sin

2

P=

PR

2

QR

2

=

125

100

=

5

4

solution

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