Question

in a right triangle sin(2x) = cos(3x-10) what is the value of x

Answer 1

Answer:

$\rm x = 20^{\circ}$

Step-by-step explanation:

We have,

$\rm \sin (2x) = \cos (3x-10)$

We know that,

$\rm \sin (90^{\circ} - θ) = \cos θ$

$\rm \sin (2x) = \cos (90^{\circ} - 2x)$

$\rm \cos (90^{\circ} - 2x) = \cos (3x-10)$

$\rm 90 - 2x = 3x-10$

$\rm 90 +10 = 3x+2x$

$\rm 5x = 100$

$\rm x = 20^{\circ}$