Math, asked by manasvimannmalik, 7 months ago

In a right triangle the two acute angles are in the ratio of 7 : 11. Find the measure of the smaller acute angle

Answers

Answered by Janvi1012
1

Answer:

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Step-by-step explanation:

let the common ratio be x

first angle=7x

second angle=11x

7x+11x+90=180

18x=90

x=90/18

x=5

smaller angle=7x

=7×5

=35°

Answered by saurabhr777
1

Step-by-step explanation:

According to the problem:

Sum of angles of a triangle =180

Let us consider the acute angles =11x and 7x

Implies that

180

−90

=11x+7x

Implies that

90=11x+7x

Implies that

90=18x

x=

18

90

Implies that

x=5

Hence the acute angle is

7×5=35

and

11×5=55

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