In a right triangle the two acute angles are in the ratio of 7 : 11. Find the measure of the smaller acute angle
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Answer:
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Step-by-step explanation:
let the common ratio be x
first angle=7x
second angle=11x
7x+11x+90=180
18x=90
x=90/18
x=5
smaller angle=7x
=7×5
=35°
Answered by
1
Step-by-step explanation:
According to the problem:
Sum of angles of a triangle =180
∘
Let us consider the acute angles =11x and 7x
Implies that
180
∘
−90
∘
=11x+7x
Implies that
90=11x+7x
Implies that
90=18x
x=
18
90
Implies that
x=5
Hence the acute angle is
7×5=35
∘
and
11×5=55
∘
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