In a rigid container NH3 is kept at certain temperature if on doubling the temperature it is completely dissociated intocN2 and H2 find the final pressure to initial pressure
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- Ratio of final pressure to initial pressure is 4.
Given-
- Container is rigid which means volume is constant.
- Initial temperature = T₁
- Final temperature = 2 T₁
Reaction is -
2 NH₃ → N₂ + 3 H₂
Volume and moles is constant.
By applying ideal gas equation-
P V = n R T, where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant and T is the temperature.
V and n is constant so P ∝ T
P₁/P₂ = T₁/T₂
1 mol of NH₃ gives T₁ so
2 mol of NH₃ gives 2 T₁
So,
P₂/P₁ = 2 T₁ × 2/ T₁ = 4
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