Question

In a RL circuit shown in the figure resistance R=30ohm, reactance R=40ohm and peak emf = 220V.
calculate: a)Impedance
b) phase difference
c) the peak value of the current in the circuit. ​

Answer 1

Answer:

In a RL circuit shown in the figure resistance R=30ohm, reactance R=40ohm and peak emf = 220V.

Answer 2

Given:

Resistance R = 30 ohm

Reactance $X_{L}$ = 40 ohm

Peak EMF E = 220 V

To find:

Impedance (Z)

Phase difference (Ф)

Peak current (I)

Solution:

(a) Impedance (Z):

• Z = $\sqrt{R^2+X_{L} ^2}$

             =$\sqrt{30^2+40^2}$

• Z = 50 ohm

(b) Phase difference (Ф)

• cos Ф = $\frac{R}{Z}$ = $\frac{30}{50}$

• Ф = $cos^{-1}$ (0.6)

(c) Peak current (I):

• As per Ohm's law: V=IZ

        ⇒ I = $\frac{V}{Z}$ = $\frac{220}{50}$

• I = 4.4 A