Question

in a rocket fuel burns at the rate of 1 kg s.
fuel is elected from the rocket with a velocity on
60 km/s. This exerts a force on the rocket equal
to a= 60x1-10
(1) 6000 N
07 (2) 60000 N am
(3) 60 N ​

Answer 1

Answer:

6000N

Explanation:

This Exerts Force 6000N

Answer 2

$\huge{\bold{\underline{\underline{....Answer....}}}}$

$\huge{\bold{\underline{Given:-}}}$

$\large{ \frac{m}{t} = 1 \: kg/s}$

v = 60 km/s.

Converting in to S.I. units

v = 60 × 1000 m/s. (1Km = 1000m)

v = 60,000 m/s.

$\huge{\bold{\underline{Explanation:-}}}$

As we know,

$\large{\bold{F = \frac{dp}{dt}}}$

It becomes

As P = mv

$\large{ \bold{F = \frac{d(mv)}{dt}}}$

The mass is not constant here but velocity is constant.

It becomes

$\large{\bold{ \implies F = v. \frac{dm}{dt}}}$

Taking over a large interval of time.

$\large{ \implies F = v \times \frac{m}{t}}$

Substituting the values

$\large{ \implies F = 60,000 \times 1}$

As rate of change of mass is equal to the rate of fuel burning.

I.e. $\large{ \frac{m}{t} = 1 \: Kg/s}$

$\huge{\boxed{\boxed{F = 60,000N}}}$

So,the Force exerted on the rocket is 60,000N(option- 3).