Question

In a rocket fuel burns at the rate of 1 kg/s. This fuel is ejected from the rocket with a velocity 60km/s . Find the force exerted on rocket​

Answer 1

▶ Solution :

Given :

▪In a rocket fuel burns at the rate of 1kgps

▪Velocity of ejection of fuel = 60kmps

To Find :

Force exerted on rocket.

Concept :

✏ This question is completely based on newton's second law of motion.

Mathematically,

F = ma

Calculation :

$\implies\sf\:F=\dfrac{dm}{dt}\times v\\ \\ \implies\sf\:F=1\times 60\times 10^3\\ \\ \implies\boxed{\bf{\orange{F=60\:kN}}}$

▪ Force is a vector quantity.

Answer 2

Answer:

The force exerted on the rocket will be 60,000 N.

Explanation:

Given;-

   Rate at which fuel is burning, dm/dt = 1 kg/s

     Velocity of gases, v = 60 km/s

                                     v = 60,000 m/s

Let the accelerating force on the rocket be 'F'

We know by formula that;-

              F = v dm/dt

Putting the given values in the formula, we get;-

               F = 60,000 × 1

               F = 60,000 N

Hence, the force exerted on the rocket will be 60,000 N.

Hope it helps! ;-))