In a rocket motor fuelled with Heptane (C7H16) How many kg of liquid oxygen should be provided with each kg of heptane sample (which is 50% pure) for its complete combustion :
Answers
Answer:
1.76 kg
Explanation:
The above is the example of combustion reaction,
Therefore, C7H16+11O2→7CO2+8H2O
Since, 100g of C7H16 react with 11×32g=352,
1g of C7H16 →352/100=3.52g
1kg of C7H16→3.52kg
Therefore, % purity of 50 %= 3.52×50/100=1.76 kg....
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Given : In a rocket motor fuelled with Heptane (C7H16) which is 50% pure.
To find : amount of liquid oxygen should be provided with each of kg of heptane sample for its complete combustion.
solution : combustion reaction of heptane,
C7H16 + 11O2 => 7CO2 + 8H2O
one mole of C7H16 reacts with 11 moles of oxygen to produce 7 moles of CO2 and 8 moles of water.
molar mass of heptane = 12 × 7 + 16 = 84 + 16 = 100g/mol
so, 100g of heptane reacts with 32 × 11 = 352g of oxygen.
⇒1kg of heptane reacts with 3.52 kg of oxygen.
so, each of kg of heptane, amount of liquid oxygen is required = 50% of 3.52 kg [ as purity of heptane is 50% ]
= 3.52/2 = 1.76 kg
Therefore 1.76 kg of liquid oxygen should be provided with each of kg of heptane sample.