Physics, asked by Sruthypotter45651, 11 months ago

In a rocket of mass 1000 kg fuel is consumed at a rate of 40 kg/s the velocity of gas ejected from the rocket is 5*10^4 m/s the thrust on a rocket is

Answers

Answered by sid590
5

fuel consumption=40kg/s

velocity of ejection=5* 10^4m/s

thrust= fuel cons * vel of ejection

= 2*10^6N

Answered by Physicsmaniac
1

Answer:2×10^6 N

Explanation:

F=V.dm/dt=5×10^4×40=2×10^6N

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