Question

In a sale, prices are reduced in the ratio 5:6. Find the sale prices of aricles whose normal prices are ₹531.72​

Answer 1

The given data in the question are are as follows

The ratio in sales, prices are reduced from $6$ to $5$

The normal prices of sale is Rs. $531.72$

so, $\frac{531.72}{6} =\frac{sale price of article}{5}$

taking cross multiplication we get,

$6 \times sale price of article=5 \times 531.72$

shifting $6$ into right side of denominator

sale prices of article=$\frac{5 \times 531.72}{6}$

Multiplying $5$ by $531.72$ we get,$2,658.6$

dividing  $2,658.6$ by $6$ it get $443.1$

Therefore, sale prices of article is $443.1$

Answer 2

Answer:

The given data in the question are are as follows

The ratio in sales, prices are reduced from 66 to 55

The normal prices of sale is Rs. 531.72531.72

so, \frac{531.72}{6} =\frac{sale price of article}{5}

6

531.72

=

5

salepriceofarticle

taking cross multiplication we get,

6 \times sale price of article=5 \times 531.726×salepriceofarticle=5×531.72

shifting 66 into right side of denominator

sale prices of article=\frac{5 \times 531.72}{6}

6

5×531.72

Multiplying 55 by 531.72531.72 we get,2,658.6 we get dividing 2 and the answer was come out