in a sample of 100 nails, 18 of them have only defective heads , 12 contain defective tail ends and 9 contains both defectives . what is the probability that a nail selected at random is either a defective head or a defective tail
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Answer:
total outcomes=100
defective heads = 18
defective tails=12
both defectives ( head and tail ) = 9
:. probability of defective head
favourable outcomes
= –--------------------------------
total outcomes
= 9+18/100
= 27/100
AND probability of defective tail
= 12 + 9 /100
= 21/100
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0.21
Probability of defected heads=P(H)=18/100=0.18
Probability of defective tail ends=P(T)=12/100=0.12
Probability of Both defectives=P(H and T)=9/100=0.09
P(either a defective head or a defective tail)
P(HUT)=P(H)+P(T)-P( H and T)
=0.18+0.12-0.09
=0.21
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