In a sample of 11 gram of CO2, 3gram of carbon react with 8 gram of oxygen. Calculate the amount of CO2 formed if 6gram of carbon react with 16 gram of oxygen
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As per the given condition, when 3.0 g of carbon is burnt in 8.00 g oxygen, 11.00 g of carbon dioxide is produced. Therefore, the law of conservation of mass is proved. Then, it also depicts that the carbon dioxide contains carbon and oxygen in a fixed ratio by mass, which is 3:8.
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This is governed by the law of definite proportion. Carbon and oxygen combine in 3:8 ratio. So 11 g of carbon dioxide is formed.
Hence, in the latter case too, only 8 g of O
2
will be reacted with 3g of carbon (because carbon is the limiting reagent here ) to form 11g of CO
2
and 42 g of oxygen will remain unreacted.
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