Question

in a sample of mgco3 3.011x10^23 of mg was taken and 3.011 x 10 ^23 of co 3 was taken calculate the mass of the sample​

Answer 1

Answer:

8 gram

Explanation:

If you mean Oxygen as atoms, its molar mass is 16 g/mol, if you mean moleceule (O2) it is 32 g/mol.

I assume you meant atoms, so let’s stick with 16 g/mol.

Molar mass tells us about the weight of one mole of something. And one mole is 6.022 * 10^23 atmos/molecules (Avogadro's number). So 6.022 * 10^23 Oxygen atoms is 16 g (1 mole * molar mass).

Now you can use proportion:

6.022 * 10^23 at. = 16 g

3.011 * 10^23 at. = x g

So x = 8g

Or you can check, how many moles is 3.011*10^23 at. - and it is 1/2, then just multiplay moles * molar mass, so you get

1/2 mol * 16 g/mol = 8 g