in a school ,25%of student in division A are grils as are 40% of division B . if the strength of A is 40 and the division B is 60 what is the proportion of girls in combined class with both division A and B ?
Answers
Answer:
Step-by-step explanation:
the math is very simple and we have 2 solutions!
Solution 1
We have 50 students. 50 is the half of 100 because 50x2=100
40% is equal to 40/100
As we all probably know from fractions if we divide one of the numbers in the fraction, we have to divide with the same number the other one.
So, 40/100 is equal to 20/50 because 100/2=50 and 40/2=20
20/50 (which is equal to 40/100 or 40%) says that 20 girls are in the class
And if we do the subtraction, it’s 50–20=30
Answer: There are 30 boys in the class
Solution 2
We have 50 students and 40% are girls.
If we multiply 50 with 2 it gives us 100 (50x2=100)
40% is equal to 40/100
So there are forty girls in the class with supposedly 100 students.
If we do the subtraction it’s 100–40=60
And then we divide it by 2 because we multiplied the number of the students earlier 60/2=30
Answer: There are 30 boys in the class
Hope I made it clear,
Step-by-step explanation:
girls in section A:25 ×40/100
=10 Girls
girls in sectionB=40×60/100
=24 Girls
girls in section A : girls in section B = 10 :24
=5:12