Question

In a school, 35% girls and 19% boys participated in singing. Number of students in the school is 700. How many boys are there in the school? I. Number of boys are more than 200. II. More than 190 students participated

Answer 1

my answer is in decimal . my ans. is 507.22 boys

Answer 2

Statements I and II together are necessary to answer the question

Solution:

In a school, 35% girls and 19% boys participated in singing

Number of students in the school is 700

Let the number of boys in school be B

Let the number of girls in school be G

Then,

B + G = 700 ----- eqn 1

From statement 1,

Number of boys are more than 200

B > 200

From statement 2,

More than 190 students participated

Therefore,

190 <  35 % of G + 19 % of B

$190 < \frac{35}{100} \times G + \frac{19}{100} \times B$

Note that, B > 200

Then B = 300 only satisfies this condition

B + G = 700

300 + G = 700

G = 400

Then,

$190 < 0.35 \times 400 + 0.19 \times 300\\\\190 < 0.35 \times 400 + 57\\\\190 < 197$

Thus, Statements I and II together are necessary to answer the question

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