Question

In a school 38% of the students are girls if the number of boys is 1023 find the total strength of the school

Answer 1

Step-by-step explanation:

Let the number of students be x

So, the number of girls = x - 1023

percentage of girls = 38%

[(x - 1023)/x] × 100 = 38

(x - 1023)/x = 19/50

50x - 51150 = 19x

50x - 19x = 51150

31x = 51150

x = 1650

Total strength of the school is 1650

Answer 2

1650

Step-by-step explanation:

let the total strength of school be x

number of girls = 38%

= 38/100 × x

= 38x/100

number of boys = 1023

x = 1023 + 38x/100

$\begin{gathered}x - \frac{38x}{100} = 1023 \\ \frac{100x - 38x}{100} = 1023 \\ 62x = 1023 \times 100 \\ x = \frac{1023 \times 100}{62} \\ x = 1650\end{gathered}$

x−

100

38x

=1023

100

100x−38x

=1023

62x=1023×100

x=

62

1023×100

x=1650

therefore the total strength is 1650

number of girls = 1650 - 1023 = 627

hope you get your answer