Question

In a school 45students participated ina competition.All the winners got Rs 300 each also each participate who did not get a participation prize of Rs 50 if the organizer gave Rs 5000 prizes and find how mamy winners are there​

Answer 1

Let, Winners = x

Non-Winners = y

Equation 1 ---> x+y = 45 (Total Participants 45 is Given)

Winners get ₹300.
Non-Winners get ₹50.
Total Money Spent by Organisation is ₹5000

Thus we can form Equation 2.

Equation 2 ---> 300x+50y = 5000 (Total money spent is ₹5000)

=> 6x+y = 45 (Dividing it by 50)

(Eq1-Eq2) we get, 5x = 55

=>x = 11

Thus there were 11 winners.

Brainliest Please!

Answer 2

Answer:

Step-by-step explanation:

Let the winner students be x. and

the participation students who didn't get prize be y.

According to question,

x+y=45. -(1)

And. 300x+50y=5000. -(2)

By solving this both equation we get

x=11 and y=34