Math, asked by viddhyanidhi2962, 1 year ago

In a school all the students play at least one of the three indoor games -chess carram and table tennis .60 play chess 50 play table tennis 48 play carrom 12 play chess and carrom 15 play carrom and table tennis 20 play table tennis and chess so what can be the minimum no. Of students in the school

Answers

Answered by chbilalakbar
15

Answer:

Maximum students in school = 123

Minimum  students in school = 111

Step-by-step explanation:

Students play chess = A = 60

Students play table tennis = B = 50

Students play carrom = C = 48

Students play games A and C = D = 12

Students play games B and C = E = 15

Students  play games B and A = F = 20

Now

Student playing all the games = G = 12.

We can see easily that

Maximum number of students = A+B+C-D-E-F+G = 60+50+48-12-15-20+12

Maximum number of students = 123

Minimum number of students = (maximum no of students) - G

Minimum number of students = 123 - 12 = 111.

SO

Maximum students in school = 123

Minimum  students in school = 111


rbhagwane123: How g=12??
chbilalakbar: intersection of D , E and F is 12
chbilalakbar: I think it is helpful
as994409: How g =12 with full concept
chbilalakbar: The students playing all the games are 12
Answered by siddhantjadham199
27

Answer:

Step-by-step explanation: how g is 12

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