Question

In a school having 1200 students , 60% of the students are boys and the rest are girls . if 40% of the boys and 30% of the girls to like play badminton , find 1 : the number of boys that like to play badminton. 2: the number of girls that like to play badminton. 3: the percentage of students that like to play badminton.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

(1)

   NUMBER OF BOYS WHO LIKE BADMINTON =  288

(2)

   NUMBER OF GIRLS WHO LIKE BADMINTON =  144

(3)

PERCENTAGE OF TOTAL STUDENTS WHO LIKE BADMINTON =  70%

Step-by-step explanation:

PARAMETERS GIVEN,

TOTAL NUMBER OF STUDENTS = 1200

PERCENTAGE OF BOYS = 60%

PERCENTAGE OF GIRLS = 100% - 60%

                                          = 40%

SO,

NUMBER OF BOYS = 60% OF 1200

                                 = (60*1200)/100

                                 = 720

NUMBER OF GIRLS = 40% OF 1200

                                 = (40*1200)/100

                                 = 480

NOW,

(1)

   NUMBER OF BOYS WHO LIKE BADMINTON = 40% OF 720

                                                                               = (40*720)/100

                                                                               = 288

(2)

   NUMBER OF GIRLS WHO LIKE BADMINTON = 30% OF 480

                                                                               = (30*480)/100

                                                                               = 144

(3)

PERCENTAGE OF TOTAL STUDENTS WHO LIKE BADMINTON = 30%+40%

                                                                                                          = 70%

I HOPE YOU UNDERSTOOD THE QUESTION!!!

                                 !!!JAI SHREE KRISHNA!!!