Chemistry, asked by rohithrathod134, 8 months ago

In a school laboratory, beakers A, B, C and D are arranged as follows:(i) Beaker (A): iron rod dipped in iron sulphate solution(ii) Beaker (B): iron rod dipped in zinc sulphate solution(iii) Beaker (C): iron rod dipped in copper sulphate solution(iv) Beaker (D): iron rod dipped in aluminium sulphate solutionThe beaker in which a metal will deposit on iron rod is

Answers

Answered by karthikthakur4499
0

Answer:

ANSWER

The student designated as (A) made the correct observation.

In breaker (I),the solution remained colourless or unchanged in colour since no chemical reaction was possible.Actually,aluminium is placed above zinc in the activity series.

In beaker (II),no chemical reaction was possible and the solution remained colourless.

In beaker (III), the initial colour of ferrous sulphate solution was light green .It became colourless after the reaction.

Zn(s)+FeSO

4

(aq)→ZnSO

4

(aq)+Fe(s)

Blue Colourless

In beaker (IV), the initial colour of ferrous sulphate solution was blue .It became colourless after the reaction.

Zn(s)+CuSO

4

(aq)→ZnSO

4

(aq)+Cu(s)

Blue Colourless

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