Chemistry, asked by vvp9f2021r30, 3 months ago

In a school laboratory, beakers A, B, C and D are arranged as follows:(i) Beaker (A): iron rod dipped in iron sulphate solution(ii) Beaker (B): iron rod dipped in zinc sulphate solution(iii) Beaker (C): iron rod dipped in copper sulphate solution(iv) Beaker (D): iron rod dipped in aluminium sulphate solutionThe beaker in which a metal will deposit on iron rod is​

Answers

Answered by poiuytrewqheyhow
12

Answer:

Copper in Beaker C is deposited on it.

Explanation:

In beaker A there is iron sulphate solution, So iron can't displace iron.

In beaker B and D, Zinc and Aluminium are more reactive. So, Iron can't displace them.

In Beaker C, Copper is less reactive than Iron, So it can be displaced by iron to form Iron Sulphate and Copper(deposited on iron rod).

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