Math, asked by abel27, 9 months ago

In a school of 500 students, 180 likes to play
cricket, 120 likes to play football and 80
play both the games.
(a) Find how many students likes to play
Cricket or football.
(b) Find the number of students playing neither
Cricket nor football.​

Answers

Answered by kancharlaruthwik
8

Answer:

(a)220

(b) 500-220=280

Step-by-step explanation:

(a)

n(A)=180

n(B)=120

n(A⋂B)=80

n(A⋃B)=n(A)+n(B)-n(A⋂B)

Hence n(A⋃B )=180+120-80=220

(b)

500-n(A⋃B)=500-220=280

Answered by ttttttaaaaaa
0

Answer:

1) 220

2)280

Step-by-step explanation:

the number of students who like to critical to see in a reference who like to football equal to aa the number of students who like to critical to see in a reference who like to football equal to aa the number of students who like to critical to see in a reference who like to football equal to a the number of students who like to critical to see in a reference who like football equal to a FIR equal to n m c plus and minus n f c intersection f is equal to 180 + 120 - 80 is equal to 220

neither cricket nor football =500 - 22632 80

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