Question

In a school, on the first day 1 student was absent, on the second day 2 students were absent, on the third day 4 students were absent. On the fourth day 8 students were absent if same pattern continued till 6th day, how many students would be absent on the 6th day?

Answer 1

Answer:

Total 40

Absent 8

Present 40–8=32

Percent present=present/total×100

32/40×100 Division by 10 later by 4

32/4×10

8×10=80

80% present

Step-by-step explanation:

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Answer 2

Answer:

 Let the total no. of students are x . 

 No. of  students which were absent =3x . 

 No. of students which were present =32x

Now,

No. of dtudents who gove maths test =2x

No. of students who gave physics test: 4x

No. of students who gave both test =6

A denotes no. of students whogawe maths test

B denotes no. of students who gave physics test

n(A)=2xn(B)=4xn(A∩B)=6

n(A∪B)= no. of students which were present

n(A∪B)=n(A)+n(B)−n(A∩B)32x=2x+4x−6x=72

 No. of students which are absent =372=24

Step-by-step explanation:

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