In a school, on the first day 1 student was absent, on the second day 2 students were absent, on the third day 4 students were absent. On the fourth day 8 students were absent if same pattern continued till 6th day, how many students would be absent on the 6th day?
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Answer:
Total 40
Absent 8
Present 40–8=32
Percent present=present/total×100
32/40×100 Division by 10 later by 4
32/4×10
8×10=80
80% present
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Answered by
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Answer:
Let the total no. of students are x .
No. of students which were absent =3x .
No. of students which were present =32x
Now,
No. of dtudents who gove maths test =2x
No. of students who gave physics test: 4x
No. of students who gave both test =6
A denotes no. of students whogawe maths test
B denotes no. of students who gave physics test
n(A)=2xn(B)=4xn(A∩B)=6
n(A∪B)= no. of students which were present
n(A∪B)=n(A)+n(B)−n(A∩B)32x=2x+4x−6x=72
No. of students which are absent =372=24
Step-by-step explanation:
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