In a school ,on the first day 1 student was present, on the 2 day 2 student was present,on the 3 day 4 student was present , on the 4 day 8 student was present.how many students would be there on 9 th day
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Answered by
0
512 because 2 power of 0=1
2 power of 1=1
,,,,,,,,,,,,,,,,,,,,, 2=4
,,,,,,,,,,,,,,,,,,,,, 3=8 this continues.....
then 2 power of 9=512 students
2 power of 1=1
,,,,,,,,,,,,,,,,,,,,, 2=4
,,,,,,,,,,,,,,,,,,,,, 3=8 this continues.....
then 2 power of 9=512 students
BhawnaAggarwalBT:
ypur answer is wrong on second day there are only 2 students present in the school
Answered by
1
here is your answer
on first day no of students present = 2^0=1 students
second day = 2^1=2 student
3rd day = 2^2 = 4 students
4th day = 2^3 = 8 students
5th day = 2^4 = 16 students
6th day = 2^5 = 32 students
7th day= 2^6 = 64 students
8th day = 2^7 = 128students
9th day = 2^8 = 256 students
hope this helps you
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on first day no of students present = 2^0=1 students
second day = 2^1=2 student
3rd day = 2^2 = 4 students
4th day = 2^3 = 8 students
5th day = 2^4 = 16 students
6th day = 2^5 = 32 students
7th day= 2^6 = 64 students
8th day = 2^7 = 128students
9th day = 2^8 = 256 students
hope this helps you
plz mark as brainliest answer plzzzzz plzzzzzzzzzzzzz mark as brainliest answer plzzzzz
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