Question

In a school there 9 teacher including headmaster. How many committee of 4 teacher can be inckuding headmaster as a chairman.

Answer 1

Answer:

56 ways

Step-by-step explanation:

We are given that In a school there 9 teacher including headmaster.

So, Total teachers = 8

Headmaster = 1

Now we are supposed to find  How many committee of 4 teacher can be including headmaster as a chairman.

Since out of 4 , 1 post is fixed for head master

So, 3 posts are vacant for remaining 8 teachers

So, Formula : $^nC_r=\frac{n!}{r!(n-r)!}$

So, No. of possible ways of forming committee of 4 teacher can be including headmaster as a chairman.

n = 8

r = 3

Substitute the values in the formula :

$^8C_3=\frac{8!}{3!(8-3)!}$

$^8C_3=56$

Hence  No. of possible ways of forming committee of 4 teacher can be including headmaster as a chairman is 56