Question

in a school there are 1500 students out of which 930 are boys, 10 percent of boys are studying in class x,what is the probability that a student chosen randomly studies in class x given that the chosen student is a boy

Answer 1

Answer:

%age of boys in class x

10%of930=93

p(e)=no. of possible outcome÷total no. of outcome

=93÷930=10

Answer 2

The required probability is 0.1.

Step-by-step explanation:

Since we have given that

Number of students = 1500

Number of boys = 930

Number of boys are studying in class X = 10% of 930 = 93

Let A be the event that boys study in class X.

Let B be the event of getting a boy.

So, the probability that a student  chosen in class X given that he is a boy would be

$P(A|B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{93}{930}=0.1$

Hence, the required probability is 0.1.

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