Question

In a school there are two prizes for excellence in physics (Ist and IInd) two in Chemistry (Ist and IInd) and
only 1 in Mathematics (Ist). In how many ways can these prizes be awarded to 20 students?​

Answer 1

Answer:

4 students one prizes

because 20÷5= 4

Answer 2

Answer:

2,888,000

Step-by-step explanation:

Here, a student can obtain multiple award at a time.

But a student 1st in Physics cannot obtain 2nd in Physics. Same condition for chemistry.

no of way for 1st place in math or physics or chemistry = 20

no of way for 2nd place in physics or chemistry = 19

So, no of ways = 20×20×19×20×19 = 2,888,000