in a school there are two section A and B of class 10th there are 48 student of section a and 60 student in section B determine the least number of books can be distributed equally among of students of each section
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- Section A Students = 48
- Section B Students = 60
- Determine the least number of books can be distributed equally among of students of each section.
As we Have to Find the Least Number of Books, therefore we will find the LCM of Number of Students.
• LCM of Section A and B of Class 10th :
↠ LCM = 2 × 2 × 3 × 2 × 2 × 5
↠ LCM = 240
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∴ Therefore, 240 Books will be required.
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Answer:
_______________________
Given that,
- Students in Section A = 48
- Students in Section B = 60
To find,
- Least number of books distributed.
Solution:-
The reason because of which we have to find least number of books distributed among the students of each section,so we will have to find L.C.M. of number of students of each section.
L.C.M. of 48 and 60 ,
48 = 2 × 24
48 = 2 × 2 × 12
48 = 2 × 2 × 2 × 6
48 = 2 × 2 × 2 × 2 × 3
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60 = 2 × 30
60 = 2 × 2 × 15
60 = 2 × 2 × 3 × 5
L.C.M. = 2 × 2 × 2 × 2 × 3 × 5
L.C.M. = 240
240 books have to distributed among the students of each section.
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