in a school there are two sections of class 10 and the sectionr a n be there at 96 students in section a and 120 students in section B determine the least number of books required for the library of the school so that the books can be distributed equally among students of the section VIII that of the section b
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18
the least number of books required for each section is the LCM of 96 and 120
2|96,120
2|48,60
2|24,30
2|12,15
2|6,15
2|3,15
3|1,5
5|1,1
therefore, the required number of books are = 2×2×2×2×2×2×3×5=960
AbhishMehra41:
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Answered by
15
10th-A=96
2|96
2|48
2|24
2|12 96=(2^5×3^1)
2|6
3|3
|1
10th-B=120
2|120
2|60
2|30 120=2^3×3^1×5^1
3|15
5|5
|1
LCM(96,120)= 2^5×3^1×5^1
=480
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