Question

In a school there is a rectangular ground. The length of the ground is 2 more than twice the breadth of the plot. At the rate of Rs. 200 per meter it will cost the school Rs. 30,800 to fence the plot. What are the dimensions of the plot?

Answer 1

Step-by-step explanation:

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Answer 2

$Let \: a \: breadth \: of \: a \: rectangular$

$ground = b \: m$

$Length (l) = ( 2b + 2 )\: m$

$Perimeter \:of \: the \: ground (P)$

$= 2( length + breadth )$

$= 2[ (2b+2) + b ]$

$= 2( 3b+2)\: m$

/* According to the problem given */

$At \: the \: rate \: of \: Rs \: 200 \: per \: meter$

$it \: will \: cost \: the \: school \: Rs \: 30800$

$to \:fence \:the \:plot$

$Perimeter = \frac{30800}{200}$

$= 154 \: m$

$2(3b+2) =154$

$\implies 3b + 2 = \frac{154}{2}$

$\implies 3b = 77 - 2$

$\implies 3b = 75$

$\implies b = \frac{75}{3}$

$= 25 \: m\: --(1)$

$Length ( l ) = 2b + 2$

$= 2\times 25 + 2$

$= 50 + 2$

$= 52 \:m$

Therefore.,

$\red{ Length \:of \:the \: ground}\green { = 52 \:m}$

$\red{ Breadth \:of \:the \: ground}\green { = 25\:m}$

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