In a School two flowerbeds as given in the figure are available for planting. If cost of planting flowers in smaller flowerbed is Rs. 5000, find the cost of planting the other flowerbed at the same rate.
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The two triangles are similar by angle-angle test for similarity.
Ratio of sides = 12:24 = 1:2
Therefore, ratio of areas of two similar triangles
= (Ratio of sides)^2
= (1:2)^2
=1:4
Assuming area of smaller flowerbed to be x sq. m
Therefore, area of larger flowerbed = 4x sq. m
Rate of charge = Total cost / Area of field
= Rs. 5000/x per sq. m
Therefore, cost of flowering larger flowebed = Rate of charge * area of flowerbed
= 5000*4x/x
= Rs. 20,000
Ratio of sides = 12:24 = 1:2
Therefore, ratio of areas of two similar triangles
= (Ratio of sides)^2
= (1:2)^2
=1:4
Assuming area of smaller flowerbed to be x sq. m
Therefore, area of larger flowerbed = 4x sq. m
Rate of charge = Total cost / Area of field
= Rs. 5000/x per sq. m
Therefore, cost of flowering larger flowebed = Rate of charge * area of flowerbed
= 5000*4x/x
= Rs. 20,000
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