Question

in a school X , 48 students appeared for 10 class exam out of which 36 students passed. in another school y 30 students appeared and 24 students passedthe district education officer wants to give an award on the basis of pass percentage to which school he give the award?​

Answer 1

Answer:

Step-by-step explanation:

we have to find percentage of passed students in order to give prize

percentage of passed students in school X = (36/48)*100

                                                                    = 3/4 * 100

                                                                    = 3*25

                                                                    = 75%

percentage of passed students in school Y = (24/30)*100

                                                                    = (3/5)* 100 

                                                                    = 3*20

                                                                    = 60%

 so price should be given to school X

Answer 2

Answer:

School B

Step-by-step explanation:

Total 48 Students in A school,

Passed = 36

$pass \: \% = \frac{pass}{total \: students} \times 100$

$\frac{36}{48} \times 100$

$\frac{3}{4} \times 100$

3 X 25 = 75%

Now in school B, total students =30

Passed = 24

$pass \: \% = \frac{pass}{total \: students} \times 100$

$\frac{24}{30} \times 100$

$\frac{4}{5} \times 100$

4 X 20

= 80%

Hence, School B will get the award

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