Question

In a screw gauge 5 complete rotations of the screw cause it to move a linear distance
of 0.25 cm. There are 100 circular scale divisions. The thickness of a wire measured
by this screw guage gives a reading of 4 main scale division.
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Answer 1

Answer:

Explanation:

Pitch of screw gauge is 0.25/5 = 0.5 cm

Least count is 0.5/100 = 0.005 cm

Main scale reading = 4 × 0.1 cm = 0.4 cm

Please give circular scale reading

Question incomplete