Question

In a screw gauge, the pitch is of one mm and t
number of circular scale divisions is 20, hence t
least count of the instrument is
(1) 1 mm
(2) 0.1 mm
(3) 0.5 mm
(4) 0.05 mm​

Answer 1

Answer:

HI

Explanation:

Answer 2

Answer:

pitch= 1mm

circular scale divisions=20

least count= pitch/circular scale divisions

Hence, pitch= 1/20= 0.05mm