In a second order reaction,
20% of a substance is
dissociated in 40minutes.
The time taken by 80%
of its dissociation is?
Answers
Answered by
0
Answer:
160 minutes is the answer please leave a comment and follow me
Answered by
1
Answer:
For second order reaction,
When x = 20%, (a - x) = 80%, a = 100%
k
2
=
t
1
⋅
a(a−x)
x
=
40
1
×
100×(100−20)
20
=
2×100×80
1
When x = 80%, (a - x) = 20%
k
2
=
t
1
×
100×20
80
1/25t
From equations (i) and (ii),
t=
25
2×100×80
=640min
Explanation:
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