Question

In a second order reaction,
20% of a substance is
dissociated in 40minutes.
The time taken by 80%
of its dissociation is?


​

Answer 1

Answer:

160 minutes is the answer please leave a comment and follow me

Answer 2

Answer:

For second order reaction,

When x = 20%, (a - x) = 80%, a = 100%

k  

2

​  

=  

t

1

​  

⋅  

a(a−x)

x

​  

 

=  

40

1

​  

×  

100×(100−20)

20

​  

 

=  

2×100×80

1

​  

 

When x = 80%, (a - x) = 20%

k  

2

​  

=  

t

1

​  

×  

100×20

80

​  

1/25t

From equations (i) and (ii),

t=  

25

2×100×80

​  

=640min

Explanation: