in a self pollination plant what would be the minimum number of meiotic divisions required for setting 400 seeds
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The correct answer is - 500.
400 seeds of a self-pollinating plant will be produced from 400 pollen grains and 400 eggs. 400 pollen grains will be formed from 100 microspore mother cells while 400 eggs will be formed by 400 megaspore mother cells.
Number of meiotic division to produce X no. of seeds = x + x/4 meiotic divisions
For 400 seeds, the number of meiotic divisions 400 + 400/4 = 500 divisions.
400 seeds of a self-pollinating plant will be produced from 400 pollen grains and 400 eggs. 400 pollen grains will be formed from 100 microspore mother cells while 400 eggs will be formed by 400 megaspore mother cells.
Number of meiotic division to produce X no. of seeds = x + x/4 meiotic divisions
For 400 seeds, the number of meiotic divisions 400 + 400/4 = 500 divisions.
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Answer:
Explanation:
for one meiotic division 4 cells are produced
each megaspore mother cell gives 4 cells in which 3 cells degenerate remainiing will be 1 cell
by formula x+x/4
400+400/100
=500 no.of divisions
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