In a semiconductor it is observed that three quarter of the current is carried by electron and one quarter by hole if the drift speed is three times that of holes what is the ratio of electron to hole
Answers
Answered by
0
Explanation:
The ratio of electrons to holes present is 6:5
Explanation:
As we know that current density J= nqV
current density due to electrons= Je=ne q Ve
Current Density due to holes= nh a Vh
Je/Jh=[ ne/nh ]x [ve/ Vh]
3/4/1/4 = ne/nh x 5/2
∴ne/nh= 3x4x2/4x5
ne/nh=6/5
∴The ratio of electrons to holes present
Similar questions