Math, asked by goldenflame, 1 year ago

in a seminar schedule from 10 a.m. to 2:30 p.m. ,there are 2 breaks .the first tea break from 11 a.m. to 11:15 a.m. and the second is the lunch break from 1 p.m. to 1:30 p.m. find the ratio of the break time to the total duration of the seminar please send me step by step explanation

Answers

Answered by aarm20803
2
The first break is of 15 minutes and the second one is of 30 minutes.
The ratio is the division of first quantity to second quantity.
Therefore
15÷30=1/2.
thereforr the ratio is 1:2
Hope this is helpful.

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Answered by sharonr
0

Ratio of the break time to the total duration of the seminar is 1 : 6

Solution:

In a seminar schedule from 10 a.m. to 2:30 p.m

Therefore,

Total duration of seminar = 10 am to 2 : 30 pm

Total duration of seminar = 4 hours 30 minutes

\text{4 hours 30 minutes} = 4  + \frac{30}{60} = 4 + 0.5 = 4.5\ hour

There are 2 breaks .the first tea break from 11 a.m. to 11:15 a.m. and the second is the lunch break from 1 p.m. to 1:30 p.m

11 am to 11 : 15 am = 15 minutes = 0.25 hour

1 pm to 1 : 30 pm = 30 minutes = 0.5 hour

Total break time = 0.25 + 0.5 = 0.75 hour

Find the ratio of the break time to the total duration of the seminar

Break time : total duration of the seminar = 0.75 hour : 4.5 hour

Break time : total duration of the seminar = 0.75 : 4.5

Reduce to lowest terms

Break time : total duration of the seminar = 75 : 450 = 1 : 6

Thus the ratio of the break time to the total duration of the seminar is 1 : 6

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