In a seminar the number of participants in English mathematics and science are 36 60 84 respectively find the minimum number of rooms required if in each room the same number of participants are to be seated and all of them being in the same subject In a seminar the number of participants in English mathematics and science are 36 60 84 respectively find the minimum number of rooms required if in each room the same number of participants are to be seated and all of them being in the same subject
Answers
the answer in attachment
Question:
In a seminar the number of participants in English mathematics and science are 36 60 84 respectively find the minimum number of rooms required if in each room the same number of participants are to be seated and all of them being in the same subject.
Step-by-step explanation:
Number of participants in each room is the HF of 36, 60 and 84. (As rooms are minimum and participants are maximum.)
LCM of 36 = 2 × 2 × 3 × 3
LCM of 60 = 2 × 2 × 3 × 5
LCM of 84 = 2 × 2 × 3 × 3 × 3
Now,
HCF of 36, 60 and 84 is 12.
Therefore, in each room 12 participants can seat.
Now,
Number of rooms required = (Total number of participants)/(Participants in each room)
= (36 + 60 + 84)/12
= 180/12
= 90/6
= 15
Therefore, the number of rooms required is 15.