In a seminar, the number of participants in Mathematics, Physics and Chemistry are 60, 96 and 144 respectively. Find the number of rooms required if in each room, the same number of participants are to be seated and all of them are to be in the same subject.
Answers
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Total number of rooms required is 25
GIVEN:
Number of participants in Mathematics= 60
Number of participants in physics = 96
Number of participants in chemistry = 144
TO FIND:
Number of rooms required
SOLUTION:
To find the number of rooms maximum number of participant should be seated in the rooms.
Since, each room should accommodate same number of participants and all the participants should be in the same subject
So, the number of participants should be the Highest common factor of 60, 96 and 144.
Prime factorisation of 60, 96 and 144 are as follows -
60 = 2² × 3 × 5
96 = 2² × 2² × 2 × 3
144 = 2² × 2² × 3²
HCF of 60,96 and 144 = 2² × 3 = 12
So,
Total number of rooms required =
Total number of participant / 12
60+ 96 + 144 / 12
= 300/12
= 25
Hence, Total number of rooms required is 25
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