Question

in a sequence an = n2-1 then an+1 is equal to

Answer 1

Please find the attached solution.

Answer 2

Answer:

$a_{n+1}=n(n+2)$

Step-by-step explanation:

We have been given the sequence

$a_n=n^2-1$

Substitute n = n+1 to find the required sequence

$a_{n+1}=(n+1)^2-1\\a_{n+1}=n^2+2n+1-1\\a_{n+1}=n^2+2n\\a_{n+1}=n(n+2)$

Hence, the value of $a_{n+1}\text{ is }n(n+2)$