Question

In a sequence of 10 consecutive even numbers, the sum of the first 4 numbers is 412. What is the sum of the last 4 numbers in the sequence?

Answer 1

Let the 10 consecutive even no. be x, x+2, x+4, x+6, x+8, x+10, x+12, x+14, x+16, x+18

Therefore ATQ,

x + x+2 + x+4 + x+6 = 412

4x + 12 = 412

x = 100

Therefore, The sum of last 4 numbers

100 + 12 + 100 + 14 + 100 + 16 + 100 + 18 = 460 Answer