Question

in a series L-C circuit, if L = 10-3 H and
C= 3x10-7 F is connected to a 100 V-50 Hz a.c.
source, the impedance of the circuit is..
​

Answer 1

Answer:

The answer is (4) None of these

Explanation:

The detailed explanation is shown in the following image

"I hope this answer may help you"

Answer 2

Answer:

Option 3 is correct

Z = 10^5/3 π -  π/10

Explanation:

The Impedance Triangle for a Series RLC Circuit

Z^2  = R^2+ 〖(Xc-Xl)〗^2

In our case R= 0;

Z = Xc – Xl;

Xl = 2 pi f L

= 2 (π) ( 50) ( 10^-3)

= 0.1 π

Xc = 1 / (2 pi f C)

    = 1 / ( 2 x π x 50 x 3x10^-7)

   = 10^5/3 π

Hence the total impedance will be;

Z = Xc – Xl

Z = 10^5/3 π - 0.1 π

Z = 10^5/3 π -  π/10

Option 3 is correct