In a series LCR circuit, the voltage across the resistance, capacitance and inductance is 10
V each. If the capacitance is short circuited the voltage across the inductance will be
a.10V
b.10√2V
c.10/√2V
d.20V
gopalsibapaul01:
since voltage across L,C and R is same equal to 10v therefore R=xl=xc also,total voltage in the circuit is I[ R^2 +(xl_xc)^2]1/2. when capacitor is short circuited current in the circuit l=10/(R^2+L^2)1/2 =10/√2R. potential drop across industance =Ixl=IR=(10/√2)v
answer_(10/√2)v
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Answer:
c)10/√2V
Explanation:
c)10/√2V answer...
pls explain...!
please wait me 1 hour..because my exam.
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