in a series LCR circuit which is connected to an AC voltage source choose the incorrect statementthe equation of an alternating voltage is V = 220 Sin Omega T + 5 by 6 and the equation for current is I=10sin(omega t +π\6)
the impedence of the circuit
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Answer:
We know that , Z=
I
0
E
0
Given, E
0
=220V and I
0
=10A
so Z=
10
220
=22 ohm
ϕ=[
6
π
−(−
6
π
)]=
3
π
p
a
=
2
E
0
×
2
I
0
×cosϕ
=
2
220
×
2
10
×cos
3
π
=550W
Explanation:
hope it helps
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