Question

in a series of successive measurements in an experiment, the readings of the period of oscillation of a simple pendulum were found to be 2.63s,2.56s, 2.42s, 2.71s,2.80s.Calculate the mean value of the period of oscillation.​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Mean= 2.63 + 2.56 + 2.42 + 2.71 + 2.80 / 5

         = 2.624 s

Absolute Error= delta a1 = 2.63 - 2.62 = 0.01

                           delta a2 = 2.56 - 2.62 = 0.06

                           delta a3 = 2.42 - 2.62 = 0.0205

                           delta a4 = 2/71 - 2.62 = 0.09

                            delta a5 = 2.80 - 2.62 = 0.18

Delta a mean = 0.01+0.06+0.20+0.09+0.18 / 5

                      = 0.108 = 0.115 s

Relative Error= 0.115 / 2.6 = 0.04 s

Percentage Error = Delta a mean / a mean x 100

                             = 0.11 / 2.6 x 100

                             = 4%

Hope This Helps You :D