Question

In a series RC circuit a resistance and capacitance are connected in series in such a manner it takes 220V ac supply. the values of resistance and capacitance are 20 ohm and 0.6 microfarad. The supply frequency is 50Hz of the circuit. Determine total impedance of the circuit.

Answer 1

Answer:

neet

hdklsbbfnrl

dnjdke

Answer 2

Given,

In a series RC circuit,

AC supply $=220V$.

Resistance, $R=20ohm$.

Capacitance, $c=0.6$μ$F$.

Frequency, $f=50Hz$.

To find,

Impedance of the  circuit, $Z.$

Solution,

We know that,

Impedance of a series RC circuit is calculated by,

$Z=\sqrt{R^{2}+X_{c}^{2}}$

Where,

$X_{c}=\frac{1}{2\pi fc}$

And,

$c=0.6$×$10^{-6}F$

⇒$c=6$×$10^{-5}F$

So,

$X_{c}=\frac{1}{(2)(3.14)(50)(6*10^{-5})}$

⇒$X_{c}=\frac{1}{(314)(6)(10^{-5})}$

⇒$X_{c}=\frac{1}{1884*10^{-5}}$

⇒$X_{c}=\frac{100000}{1884}$

⇒$X_{c}=53.07ohm$

So,

Impedance will be,

⇒$Z=\sqrt{(20)^{2}+(53.07)^{2}}$
⇒$Z=\sqrt{400+2816.42}$

⇒$Z=\sqrt{3216.42}$

⇒$Z=56.71ohm.$

Therefore, impedance of the given RC circuit is $56.71ohm$.