Physics, asked by kamaljeetsingh8907, 7 months ago

In a series resonant circuit, having L,C and R as its elements,
the resonant current is i. The power dissipated in circuit at
resonance is
(a)i²R/(⍵L-1/⍵C) (b) zero
(c) i² ⍵L (d) i² R.

Answers

Answered by suryanssahu

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are you really offering that points for the answer

Answered by Jasdeep145

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✌️Hope It Helps✌️

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