In a series RLC circuit, R=2ohm, L=1mH and C=0.4microfarad.What is resonance frequency in rad/sec?
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Answer:
please give me some point I have no points
Answered by
1
Given :
R = 2 ohm
L = 1 mH = 1 × 10⁻³ H
C = 0.4 μF = 0.4 × 10⁻⁶ F
To Find :
Resonance angular frequency
Solution :
In a resonant LCR circuit, current and EMF are in the same phase.
In purely resistive circuit or resonant LCR circuit, Inductive reactance () is equal to Capacitive reactance (). So,
=
⇒ = Lω₀
⇒ ω₀ =
Resonant angular frequency (ω₀) =
=
=
= 5 × 10⁴ rad/sec
Therefore, in the given LCR circuit, the value of resonant angular frequency is 5 × 10⁴ rad/sec.
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