Question

In a series Sₙ = 3n²+2n then t₄=

Answer 1

Answer:

Sₙ = 3n²+2n then t₄=

S4 = 3(4)^2+2(4)

S4= 48+8

S4=56

T4=56

Answer 2

Step-by-step explanation:

S1=3(1)^2+2(1)

S1=3+2=5

S1=t1

t1=5

S2=3(2)^2+2(2)

=12+4=16

S2=16

t2=S2-S1

t2=16-5

=11

d=t2-t1

=11-5

=6

t4=t1+3d

=5+3(6)

=5+18

=23

hence, t4=23